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Video Transcription

2 only applies to the x, not to the 3.

Now, if we think of 3 as 3 over 1,

we have a product of two fractions in our numerator,

and so try it before going on.

One way to simplify would be divided by a fraction.

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I can multiply by the reciprocal,

and get 4y cubed,

y to the fifth, well, the numerator here is 4y to the 8th,

and so my final answer is just 4y to the 8th.

Alternatively, I could decide to use

the quadrature of 3 plus 5, or 8.

We'll use this principle again in the next preface.

In this example, notice that I have y's in the numerator,

and in the denominator, and also z's in the denominator.

In order to simplify, I'm going to give all my y's either in the numerator or the denominator,

and similarly for this example. Since I have all my y's in the denominator,

let me move this y to the 3 down here,

and we get our y to the negative 3.

This is the principle here that a positive exponent in the numerator

Oh shit.

Blah, blah.

I'm going to go to bed.

I'm going to sleep.

So, uh, what?

Oops, yeah.

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